Kogorous Riddle Thread and eworms Deduction Thread

[c-square]

Anyway my riddle:
A mother is 26 years older than her child.
In six years she will be five times older than her child.
What is the father doing right now?

Staying up late rocking his baby to sleep...  (Trust me, I know.  I've been there..)

Spoiler:

The child is 6 months old (= 0.5 years).

m = c + 26
m + 6 = 5 * (c + 6)

c + 26 + 6 = 5 * (c + 6)
c + 32 = 5c + 30
4c = 2
c = 0.5
m = 26.5

[sstimson]

sorry for being late but my laptop was so slow yesterday.....

Ok, really easy one. Hint: It is supposed to be a riddle and not a math assignment ;P

A bell-ringer needs three seconds to ring the bell for 4:00. How long does he need for 12:00

Yes I know NOT a math problem but still

For 4:00
to ring the bell would need 4 pull downs and three times for the bell rope to return to normal
so the bell rope must move 7 times in those three seconds or each bell rope move takes 3/7 seconds

For 12:00 we get 12 pull down and 11 times for the bell rope to return to normal
that is a total of 23 rope movements. We already know that each movement takes 3/7 of a second
so to ring the bell 12 times takes 23*(3/7) seconds or 69/7 Seconds or 9.85714286 Seconds

You're assuming the bell-ringer involves pulling a rope.  It could be an electrical bell-ringer that has a hammer that simply hits the bell.

Granted but still there is two parts. Part one moving the hammer to strike the bell. Step two moving the hammer back to hit the bell again. And thus the math still holds. It should take about 10 seconds to strike the bell 12 times. ( Replacing the hammer moving to hit the bell for the pull down, and replacing moving the hammer back to start for the bell rope moving up.

But also look at it like this
4 rings 3 seconds
Another 4 rings 3 seconds
as in 8 rings 6 seconds
Another 4 rings 3 seconds
so 12 rings 9 seconds
granted there is a little lag twice between the fourth ring and the fifth and between eighth ring and the ninth that accounts for the time being just under 10 seconds as each add another 3/7 seconds or a total 6/7 seconds again making it just under ten seconds.

[Kogorou]

Anyway my riddle:
A mother is 26 years older than her child.
In six years she will be five times older than her child.
What is the father doing right now?

Staying up late rocking his baby to sleep...  (Trust me, I know.  I've been there..)

Spoiler:

The child is 6 months old (= 0.5 years).

m = c + 26
m + 6 = 5 * (c + 6)

c + 26 + 6 = 5 * (c + 6)
c + 32 = 5c + 30
4c = 2
c = 0.5
m = 26.5

And now I realize that there is a mistake in my riddle

A mother is 21 years older than her child.
In six years she will be five times older than her child.
What is the father doing right now?

Do the math again, I am really really really sorry about that.
And please^^

It's still your turn because you showed the right way of solving that riddle.

Edit:
I checked the numbers again.. I still wonder in what mind I wrote that.
Your turn c-square

[sstimson]

Anyway my riddle:
A mother is 26 years older than her child.
In six years she will be five times older than her child.
What is the father doing right now?

Staying up late rocking his baby to sleep...  (Trust me, I know.  I've been there..)

Spoiler:

The child is 6 months old (= 0.5 years).

m = c + 26
m + 6 = 5 * (c + 6)

c + 26 + 6 = 5 * (c + 6)
c + 32 = 5c + 30
4c = 2
c = 0.5
m = 26.5

And now I realize that there is a mistake in my riddle

A mother is 21 years older than her child.
In six years she will be five times older than her child.
What is the father doing right now?

Do the math again, I am really really really sorry about that.
And please^^

It's still your turn because you showed the right way of solving that riddle.

Edit:
I checked the numbers again.. I still wonder in what mind I wrote that.
Your turn c-square

Filling in for C squared.

Spoiler:

The child is 9 months before birth.

m = c + 21
m + 6 = 5 * (c + 6)

c=m-21
m+6=5((m-21)+6)
m+6=5(m-21)+30
m+6=5m-105+30
m-m+6=5m-m-105+30
6=4m-75
6+75=4m-75+75
81=4m
20.25=m
.-75=c as in 9 months before birth
So guess what Dad is up to ?

For fun C squared method for the new riddle


m = c + 21
m + 6 = 5 * (c + 6)

c + 21 + 6 = 5 * (c + 6)
c +27 = 5c + 30
c-c+27=5c-c+30
27=4c+30
27-30=4c+30-30
-3=4c
-.75=c
20.25=m

[Kogorou]

Spoiler:

The dad is making this riddle possible

Still c-square ^^

[c-square]

Actually, nine months is just a rough approximation.  It's more accurate to use 40 weeks, but even that can normally be off by up to 14 days on either side without the baby being considered premature or excessively late.

Okay, on to the next riddle.  Which, of course, means...

Palindrome Time!!

What the trick-playing brother said to his sister, who wanted to get dressed to go out in the rain:

" _ _ _   _ _ _ !   _   _ _ _   _   _ _ _ _ . "  ;D

To sstimson:

Spoiler:

Granted but still there is two parts. Part one moving the hammer to strike the bell. Step two moving the hammer back to hit the bell again. And thus the math still holds. It should take about 10 seconds to strike the bell 12 times. ( Replacing the hammer moving to hit the bell for the pull down, and replacing moving the hammer back to start for the bell rope moving up.

But what if it only takes 1/10th of a second for the hammer to strike the bell, 1/10th of a second to replace the hammer, and for the remaining the time it's just waiting to strike the next ding?

-0.1 seconds: Hammer moves to strike the bell
0.0 seconds: Hammer hits the bell, the first ring is heard
0.1 seconds: Hammer resets then waits
0.9 seconds: Hammer moves to strike the bell
1.0 seconds: Hammer hits the bell, the second ring is heard
1.1 seconds: Hammer resets then waits
1.9 seconds: Hammer moves to strike the bell
2.0 seconds: Hammer hits the bell, the third ring is heard
2.1 seconds: Hammer resets then waits
2.9 seconds: Hammer moves to strike the bell
3.0 seconds: Hammer hits the bell, the fourth ring is heard
3.1 seconds: Hammer resets then waits
3.9 seconds: Hammer moves to strike the bell
4.0 seconds: Hammer hits the bell, the fifth ring is heard
4.1 seconds: Hammer resets then waits
4.9 seconds: Hammer moves to strike the bell
5.0 seconds: Hammer hits the bell, the sixth ring is heard
5.1 seconds: Hammer resets then waits
5.9 seconds: Hammer moves to strike the bell
6.0 seconds: Hammer hits the bell, the seventh ring is heard
6.1 seconds: Hammer resets then waits
6.9 seconds: Hammer moves to strike the bell
7.0 seconds: Hammer hits the bell, the eighth ring is heard
7.1 seconds: Hammer resets then waits
7.9 seconds: Hammer moves to strike the bell
8.0 seconds: Hammer hits the bell, the ninth ring is heard
8.1 seconds: Hammer resets then waits
8.9 seconds: Hammer moves to strike the bell
9.0 seconds: Hammer hits the bell, the tenth ring is heard
9.1 seconds: Hammer resets then waits
9.9 seconds: Hammer moves to strike the bell
10.0 seconds: Hammer hits the bell, the eleventh ring is heard
10.1 seconds: Hammer resets then waits
10.9 seconds: Hammer moves to strike the bell
11.0 seconds: Hammer hits the bell, the final ring is heard
11.1 seconds: Hammer resets.  No more rings

As you can see, it takes three seconds for four rings, and 11 seconds for 12 rings, which was the answer given. 

[eworm]

Got it.

Spoiler:

Too bad! I hid a boot.

Nice one.

Now a riddle...
A man just can't fall asleep tonight. After some time he finally gets up and makes a phone call. As soon as somebody picks up the phone, he hangs up without a word and goes back to bed. Now he can finally sleep peacefully. Why?

Sorry it's so easy.

[Kogorou]

Spoiler:

Because he wanted to check on a person close to him that tends to stop breathing during his/her sleep. So he was worried the person might die.
He just wanted to check that the person was alive.

[Borealis]

Spoiler:

The person he called was physically close to him (next hotel room, next flat, whatever) and snorrring louder than a chainsaw. He called him to wake him up

[eworm]

Borealis guessed it.

[Silver1412]

... Why do I tend to miss the riddles and come here only when there's already a solution posted ~nya?

[Kogorou]

eworm.. that is surely a happy riddle

[sstimson]

To sstimson:

Spoiler:

Granted but still there is two parts. Part one moving the hammer to strike the bell. Step two moving the hammer back to hit the bell again. And thus the math still holds. It should take about 10 seconds to strike the bell 12 times. ( Replacing the hammer moving to hit the bell for the pull down, and replacing moving the hammer back to start for the bell rope moving up.

But what if it only takes 1/10th of a second for the hammer to strike the bell, 1/10th of a second to replace the hammer, and for the remaining the time it's just waiting to strike the next ding?

-0.1 seconds: Hammer moves to strike the bell
0.0 seconds: Hammer hits the bell, the first ring is heard
0.1 seconds: Hammer resets then waits
0.9 seconds: Hammer moves to strike the bell
1.0 seconds: Hammer hits the bell, the second ring is heard
1.1 seconds: Hammer resets then waits
1.9 seconds: Hammer moves to strike the bell
2.0 seconds: Hammer hits the bell, the third ring is heard
2.1 seconds: Hammer resets then waits
2.9 seconds: Hammer moves to strike the bell
3.0 seconds: Hammer hits the bell, the fourth ring is heard
3.1 seconds: Hammer resets then waits
3.9 seconds: Hammer moves to strike the bell
4.0 seconds: Hammer hits the bell, the fifth ring is heard
4.1 seconds: Hammer resets then waits
4.9 seconds: Hammer moves to strike the bell
5.0 seconds: Hammer hits the bell, the sixth ring is heard
5.1 seconds: Hammer resets then waits
5.9 seconds: Hammer moves to strike the bell
6.0 seconds: Hammer hits the bell, the seventh ring is heard
6.1 seconds: Hammer resets then waits
6.9 seconds: Hammer moves to strike the bell
7.0 seconds: Hammer hits the bell, the eighth ring is heard
7.1 seconds: Hammer resets then waits
7.9 seconds: Hammer moves to strike the bell
8.0 seconds: Hammer hits the bell, the ninth ring is heard
8.1 seconds: Hammer resets then waits
8.9 seconds: Hammer moves to strike the bell
9.0 seconds: Hammer hits the bell, the tenth ring is heard
9.1 seconds: Hammer resets then waits
9.9 seconds: Hammer moves to strike the bell
10.0 seconds: Hammer hits the bell, the eleventh ring is heard
10.1 seconds: Hammer resets then waits
10.9 seconds: Hammer moves to strike the bell
11.0 seconds: Hammer hits the bell, the final ring is heard
11.1 seconds: Hammer resets.  No more rings

As you can see, it takes three seconds for four rings, and 11 seconds for 12 rings, which was the answer given. 

This will be my last note on this. We are assuming a perfect world. But You and I are not adding two real world components.

One would be the time it takes to changes states from moving back to moving forward, or from moving forward to moving back. The way it is current you and I both have this time at zero, but the the real world, some time is required for the change of state to happen.

The second matter is friction. Again you and I have this at zero, but in the real world the more times something is done is a row, the more stress on either the bell rope or the hammer. This mean that will warm up and more force will be required to keep the rope , or hammer moving. Our simple example has this as a constant, but it explains why it get harder to keep the bell ring as you must put a little more force into each ring.

Also Notice you started back in time a tenth of a second. So your example does not work. Your hammer rings the bell in 3.1 seconds for 4'o clock and 11.1 seconds for 12'o clock, over the 3 seconds allowed.

The math I showed has each part and to add the real world part of hover and friction, as in to go from starting to pull the bell rope, it moving the bell enough to ring, and then hover takes less then 1/2 a second (.4285) seconds  making the four rings take 2.995 seconds (Error because of rounding) and 9.8555 seconds for twelve rings.

By the way, anyone please explain why my bell with a longer time to swing (.42) takes less time for 12 o'clock then c-squared very short (.1)
swing?

[Borealis]

3 friends finish playing cards for chips. (like casino-chips, not potato chips;) )
after 5 rounds, Andy has 8 chips, Brian has 9 and Charlie has 10.
In every round, the looser has doubled the two winner's amount of chips.

How many did each of them have before the first round?

[Silver1412]

Uhh... Math. I'm too lazy to do that in the evening ~nya.