eworm wrote:
Hm, okay, that makes sense...
So bandit 3 gets 1 coin, bandit 2 gets nothing and the rest goes to the leader, bandit 3...
And bandit 1 agrees because if he doesn't, there will be only two bandits left, with him being the less important one...
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.
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You know, I can't help but think that if there were two bandits left - bandit 2 and bandit 1 - they'd abandon the rules and just fight over the coins.
If it would be more realistically, they would.
But for this riddle, they won't do that
Keyhole drawn by Yuri Iwamoto <3
Spoiler: Secret Santa gift from Commi-Ninja <3
A Black Organization Christmas Carol (need to fix the link)
VQ wrote:
Bandit 2 doesn't have a choice, he knows that if bandit 4 dies, bandit 3 would give bandit 1 just one coin and keep 49 coins for himself and bandit 2 would get nothing, bandit 1 would accept because he knows that if 3 dies, bandit 2 could keep all the coins voting for himself (50%).
And how about he gave bandit 2 some coins instead of bandit 1? After all bandit 2 is more important and that would make more sense. I just don't see why it would have to be bandit 1.
because if bandit 3 give coins only to bandit 2, bandit 2 will know that bandit 1 will decline. and because all of them will want to maximize their own profit bandit 2 will also decline meaning bandit 3 will be dead.
am i right VQ?
You are right, all the bandits want to maximize their own profit, bandit 3 can't just give some coins to bandit 2 because he knows bandit 2 could just vote to kill 3 and keep all the money for himself, so he decides to give one coin to bandit 1 because bandit 1 knows that he will get nothing if bandit 3 dies.
but yes, this is just the pirate riddle as VQ noted (and VQ's answer is right), with terms switched up to make it not as easy to google if someone decided to do that.
The easiest way to solve it is to look at the 2-bandit case (where the more important one gives himself all the coins and leaves the other one nothing), and then work up from there.
Suggestion. make two tic toe boards one with dots in ever square. do the same with an X. second X put dots in ( there should be four). Sorry But I seen this cypher before in a code book and so I will only give that hint.
I had to look up the code-assignment but maybe this is it.
Spoiler:
It's wirtten in Pigden cipher aka masonic cipher.
The solution is:
S H E R R I N F O R D
The last hint was the one that triggered me.
A pig lives in a pen. pigpen -> pidgen (sounds nearly the same)
All you have to do then is to aplly the decoding and there you go.
I had to look up the code-assignment but maybe this is it.
Spoiler:
It's wirtten in Pigden cipher aka masonic cipher.
The solution is:
S H E R R I N F O R D
The last hint was the one that triggered me.
A pig lives in a pen. pigpen -> pidgen (sounds nearly the same)
All you have to do then is to aplly the decoding and there you go.
Spoiler:
Correct, actually this geometric substitution cipher is called Pigpen cipher or Freemason's cipher (hence, the hints): http://en.wikipedia.org/wiki/Pigpen_cipher.
BTW sstimson's message says Sherlock Holmes, you know the legendary detective.
Your turn Kogorou.
"True genius resides in the capacity for evaluation of uncertain, hazardous, and conflicting information."
I had to look up the code-assignment but maybe this is it.
Spoiler:
It's wirtten in Pigden cipher aka masonic cipher.
The solution is:
S H E R R I N F O R D
The last hint was the one that triggered me.
A pig lives in a pen. pigpen -> pidgen (sounds nearly the same)
All you have to do then is to aplly the decoding and there you go.
Spoiler:
Correct, actually this geometric substitution cipher is called Pigpen cipher or Freemason's cipher (hence, the hints): http://en.wikipedia.org/wiki/Pigpen_cipher.
BTW sstimson's message says Sherlock Holmes, you know the legendary detective.
Your turn Kogorou.
I know why he said Sherlock Holmes But that can't be possible because even if you don't know what the signs mean Sherlock Holmes doesn't have the same character twice in a row
So let's see a something for you:
Let's make this simple I don't want to keep you waiting ^^
One snowy night, Sherlock Holmes was in his house sitting by a fire. All of a sudden a snowball came crashing through his window, breaking it.
Holmes got up and looked out the window just in time to see three neighborhood kids who were brothers run around a corner. Their names were John Crimson, Mark Crimson and Paul Crimson.
The next day Holmes got a note on his door that read "? Crimson. He broke your window."
Which of the three Crimson brothers should Sherlock Holmes question about the incident?
With your 'GREAT' riddles / mysteries you might be taking too much poetic license. As such I will look over the riddle, and if I think it might actually solvable will take a shot at it. Otherwise I will critique it and let you know why I think you took too much poetic license and stay out of it. Kogorou your last riddle and the box in the window was like that. Eworm, your missing news report did it for you. If you really want others to try your riddles, you need to play more fair. And my offer still stands. I will be glad to stay out and help either of you with your riddles as to make sure you keep the poetic license to a minimum.
Glad you enjoyed my short cypher. I have read a few books on the subject and am very good at solving newspaper ones.
But that can't be possible because even if you don't know what the signs mean Sherlock Holmes doesn't have the same character twice in a row 
