soratothamax wrote:
I believe the scarred Akai could be Bourbon, but I don't believe Okiya is Akai in disguise.
Some arguments people have used:
1. Fake Akai used his left Hand
First off, real Akai could be ambidextrous (be able to use both hands), which is not uncommon for FBI members for undercover purposes.
2. Shinichi let Okiya stay in his house. Why would he do that if he were the enemy?
Of course, Shinichi wouldn't let a threat stay in his house, but Shinichi could also well know how far the person will go. Shinichi might also want to see if this person really is Bourbon. He might also want to use evidence left behind by Bourbon in his home. If Bourbon decides to leave, he can find evidence easily based on habits, phone calls, etc that he knows will be too out of the ordinary for him. He might have left a microphone chip or something to listen in on him.
To me there was a reason the supposed "fake Akai" left a message for Jodie-sensei. And there is a reason Okiya is around Sherry. I believe Okiya knows Sherry somehow, but not as Akai. He seems out-of-character for Akai. Okiya could be Sherry's father, whom she never met. Fake Akai could be Bourbon.
Okiya could be Bourbon, and fake Akai could be Akai.
1. Akai is left hand dominant, even if he is good with his right hand. He would use his left is he had the choice to. Also ambidexterity is rare, regardless of whether you are an FBI agent or not. It is NOT true that FBI agents are often ambidextrous in real life. None of the FBI agents in DC are shown to be ambidextrous either.
2. There are a couple of problems with your theory that Conan put Okiya in his house to observe him.
For fuller explanations see here. Conan seems to know about Okiya’s address despite having never met him. That seems to indicate that Conan knew about Okiya before meeting him. How would Conan know about a B.O. member like that? I doubt Conan could have figured it out in just one case because there was no evidence beyond Okiya being smart and referencing Sherlock Holmes, and Haibara wasn't sure which guy was giving off the aura. Conan is cautious, he wouldn't just let some random guy he thinks
might be a syndicate member live in his house. Also, how in the heck would Conan know how far a particular member would go? Conan isn't omnipotent. He had no idea how far Vermouth would go until he made the connection to Chris Vineyard and pieced together the reasons behind her strange actions with evidence.
While the saying goes keep your friends close and your enemies closer, letting a syndicate member live next door is a bloody ridiculous idea because Conan would be putting everyone he cares about in danger. There is no way that Conan would let a potential B.O. agent live near Haibara since, as neighbors, they have a high chance of meeting. A syndicate agent with any observational talent would figure out Haibara was Sherry. Anyone who knows her would probably be murdered. Also, by letting Okiya live in the house, it is certain that Okiya will find out Shinichi is alive. Conan himself basically told Okiya that Shinichi was alive when loaning his house keys out. If Okiya were a B.O. agent, that would mean an inevitable death sentence for everyone Conan knows, including Ran, because the B.O. would want to erase everyone who might know Shinichi was still alive and what he was investigating since Shinichi may have left compromising hints or the like. Basically, a B.O. agent living next door who isn’t Vermouth or similar is a death sentence.
Conan previously acknowledged that his house would be one of the best places so spy on Haibara and him from. It stands to reason that he might consider an ally like Akai living there a bonus despite the risk of Akai figuring out that Conan is Shinichi.
Jodie does not know scar Akai left her the message, she only assumed he did. Okiya could have left it as well.
He was smart enough to figure out Conan was Shinichi, so why wouldn't it be Eisuke? (Yes I like making random pointless guesses. I'm only two inches away from saying Okiya is Ayumi 
)
/off-topic