Kogorous Riddle Thread and eworms Deduction Thread

[MDavid]

I know frequency analysis. Next time I won't post a lazy answer, my bad.

But like this I have some time to finish the next case. I want it to be elaborated unlike my previous.

[miyano_shiho]

Even though I know the answer how is it really done

Frequency Count

6-2, U-2, 9-2, E-3, 5-1, 4-3, W-2, R-1, 3-1, O-1,  K-1

4 E 6 U 9 W 5 R 3 O K

the most frequent letter is E followed by TAONRISHD

6u9e 6u54wr 9e w34e0k4!

[spoiler]

but E here is in a two letter word and there no such words

you got the pair 6u twice and th is the most most likely pair

(Yes I have read code books and am very good at newspaper codes without cheating. For now see the wiki article on Cryptanalysis

6u9e 6u54wr 9e w34e0k4!
Th-- Th---- -- -------!

now that T is out and looking at the pair 9e at is common but T is solved? so as but thas is not a word so trying is

6u9e 6u54wr 9e w34e0k4!
This Th---- is ---s---!

back to the Frequency Count

E=S 6=T U=H 9=I 4 W 5 R 3 O K

got three 4 so it might be E

6u9e 6u54wr 9e w34e0k4!
This Th-e-- is --es--e!

E=S 6=T U=H 9=I 4=E W 5 R 3 O K

got two W and missing A so it might be A

6u9e 6u54wr 9e w34e0k4!
This Th-ea- is a-es--e!

the next letter N does not seem to fit but O might
thoe ,eao, aoe oe are all noes so eso

and o might be 0

E=S 6=T U=H 9=I 4=E W=A 5 R 3 0=O K

6u9e 6u54wr 9e w34e0k4!
This Th-ea- is a-eso-e!

looking at so-e and Letter Frequencies
missing R so make 5 R maybe

E=S 6=T U=H 9=I 4=E W=A 5=R R 3 0=O K

6u9e 6u54wr 9e w34e0k4!
This Threa- is a-eso-e!

and it looks like r is D so

E=S 6=T U=H 9=I 4=E W=A 5=R R=D 3 0=O K

6u9e 6u54wr 9e w34e0k4!
This Thread is a-eso-e!

l,c,f do not seem to fit but m does as K

E=S 6=T U=H 9=I 4=E W=A 5=R R=D 3 0=O K=M

6u9e 6u54wr 9e w34e0k4!
This Thread is a-esome!

and that makes 3 W and the final message this

E=S 6=T U=H 9=I 4=E W=A 5=R R=D 3=W 0=O K=M

6u9e 6u54wr 9e w34e0k4!
This Thread is awesome!

Final Freq. Count looks like this

ESTAIHORDMW

as to your code

A=W, bc, D=R, E=4, fg, H=U, I=9, jkl, M=K, n, O=0, pq, R=D, S=E, T=6, uv, W=3, xyz

W??R4??U9???K?0??DE6??3???

[/spoiler]

Well done.

But there's still one more thing unanswered. What's the basis for my code?
Give your answer by typing "Hello everyone" using the code.
I had just given you a hint.

[sstimson]

using your code how would you do numbers like 0, 1, 2, 3, 4, 5, 6, 7, 8, 9,?

[MDavid]

[spoiler]
Urtxb rwanmwza
[/spoiler]

Even if it is correct, I got it in an overcomplicated way. 

[miyano_shiho]

using your code how would you do numbers like 0, 1, 2, 3, 4, 5, 6, 7, 8, 9,?

I was about to say it's not applicable for numbers but I just thought of something.
1 is z.
If you already have an idea, just post it here. 

[spoiler]
Urtxb rwanmwza
[/spoiler]

Even if it is correct, I got it in an overcomplicated way. 

Nope. Remember, you can use the code you got from "This thread is awesome."
So t=6, h=u, etc.


The clue is already right in your hands...

[sstimson]

I got a theory but it likely wrong

I would guess this U4JJ0 4 4D 0L4

With blanks for V and Y as I not sure yet

Maybe this? : U4JJ0 414DC0L4.

[miyano_shiho]

I got a theory but it likely wrong

I would guess this U4JJ0 4 4D 0L4

With blanks for V and Y as I not sure yet

Maybe this? : U4JJ0 414DC0L4.

Still not the right answer.

[spoiler=More hints]2=x, 3=c, 4=v, p=-[/spoiler]

[sstimson]

P equals space?

[miyano_shiho]

No, dash. (-)

[sstimson]

Maybe this? : U4JJ0 414D70L4.

New theory

U4OO0 4F4D70J4.

[Rein]

I'm not too hot of a detective but I'm pretty good at cracking codes so this was a nice one for me  C:

U4PP0 4G4570J4

[spoiler] This looks complicated but the solution is simple. I managed to crack it about 5 or so minutes XD (Yes, I'm bragging:D I've got nothing else to brag about XD)

This is a keyboard code. Hence the hint 'the answer is already in your hands,'. Baisically you substitute the letter you need for the letter up and to the right of it on a standard keyboard.

(I looked at the riddle before I looked at the theories and I solved the 'this thread is awesome' bit through pure guesswork XD)

So working on that theory, Hello everyone turns into: U4PP0 4G4570J4 [/spoiler]

[sstimson]

5 /= R, D does, At least one exception

[MDavid]

@Rein

Nice solution!

[miyano_shiho]

I'm not too hot of a detective but I'm pretty good at cracking codes so this was a nice one for me  C:

U4PP0 4G4570J4

[spoiler] This looks complicated but the solution is simple. I managed to crack it about 5 or so minutes XD (Yes, I'm bragging:D I've got nothing else to brag about XD)

This is a keyboard code. Hence the hint 'the answer is already in your hands,'. Baisically you substitute the letter you need for the letter up and to the right of it on a standard keyboard.

(I looked at the riddle before I looked at the theories and I solved the 'this thread is awesome' bit through pure guesswork XD)

So working on that theory, Hello everyone turns into: U4PP0 4G4570J4 [/spoiler]

Very good!

Yeah, I gave hints by saying "The clue is already right in your hands" and "Give your answer by typing 'Hello everyone' using the code," thinking you might look at your keyboards and notice it. I also gave number clues: 1, 2, 3 and 4 are equivalent to z, x, c and v; although that sequence isn't as much well known as "qwerty".

Your turn, Rein.

[Rein]

Thanks XD

Hmm, I think I'll do abother code, but I don't think I can say if it's difficult or easy XD

L-7, P-8, P-5, P-8, M-5, P-6, P-3, M-4, P-8
M-5, P-2, M-2, L-9, M-2

On each line is a different word XD Makes it easier to read  :D

Hint 1: What the code above says
[spoiler] Detective Conan [/spoiler]

Umm, solve it by writing: "Akai Shuuichi"

Or you can just tell me how it works