Kogorous Riddle Thread and eworms Deduction Thread

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sstimson
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Re: Kogorous Riddle Thread and eworms Deduction Thread

Postby sstimson » December 7th, 2013, 9:06 pm

Ok, but for fun can you find another way to do the same ( Get all across safely)
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bash7353

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Re: Kogorous Riddle Thread and eworms Deduction Thread

Postby bash7353 » December 9th, 2013, 2:48 pm

Here's a second solution I've been able to find. It's pretty similar, though, I just changed one minor detail in the beginning. May not be what you were thinking of.

[spoiler]First the user transports the computer across and comes back alone. Then it looks like this:

Code: Select all

User
Virus     Computer
Antivirus

Afterwards the user brings the antivirus to the other site and brings the computer back.

Code: Select all

User
Computer     Antivirus
Virus

The user transports the computer and returns alone.

Code: Select all

User         Computer
Virus        Antivirus

Then the user takes the virus across and... Done.[/spoiler]
I think there probably are other ways that differ more from the one I mentioned.

If you don't mind, I'm just gonna post a new one:
On the ground level of a hotel there are three maiden and three vampires. There is an elevator that can take a maximum of 2 people, but can't move without anyone inside. Every time there are more vampires than maiden in one place the vampires kill the maiden. If the number of maiden and vampires that are in the same place are equal, that's okay. How can all six safely get to the top level?
Important: Everyone has to leave the elevator when getting to the top or the ground level, you can't have someone leave the level again immediately after arriving while staying in the elevator the entire time.

I may not have been able to explain the important thing there clearly. So, for better understanding, here's an example of what doesn't work:
Let's say one vampire and no maiden are on the top level. Now you send the elevator up with one vampire and one maiden. The maiden stays on the top level, while the vampire goes back down without ever leaving the elevator. On the top level you'd have one each, which is fine.
The reason this doesn't work is everyone needs to leave the elevator after it's arrived on the top level. At that point there are two vampires but just one maiden on the top level. Even if one of the vampires is As a result the vampires'll kill the maiden.
"Jo mere uenig du er med nogen, jo pænere skal du tale til dem. Tal om indholdet. Brug tid på indholdet. Forhold dig til det, der diskuteres. Lyt til, hvad der bliver sagt, i stedet for hvem der siger det. Hvis vi skal gøre det her med demokratiet bedre, så starter vi der."
描いた夢は叶わないことの方が多い
秀れた人を羨んでは自分が嫌になる
浅い眠りに押し潰されそう夜もある
優しい隣人が陰で牙を向いていたり

惰性で観てたテレビ消すみたいに生きる
ことを時々辞めたくなる

人生は苦痛ですか 成功が全てですか
僕はあなたにあなたに ただ逢いたいだけ
信じたい嘘 効かない薬 帰れないサヨナラ
叫べ叫べ叫べ   逢いたいだけ
sstimson
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Re: Kogorous Riddle Thread and eworms Deduction Thread

Postby sstimson » December 10th, 2013, 5:13 am

googleearth wrote:Here's a second solution I've been able to find. It's pretty similar, though, I just changed one minor detail in the beginning. May not be what you were thinking of.

[spoiler]First the user transports the computer across and comes back alone. Then it looks like this:

Code: Select all

User
Virus     Computer
Antivirus


So AntiVirus removes (kills) the virus

Afterwards the user brings the antivirus to the other site and brings the computer back.

Code: Select all

User
Computer     Antivirus
Virus

The user transports the computer and returns alone.

Code: Select all

User         Computer
Virus        Antivirus

Then the user takes the virus across and... Done.[/spoiler]
I think there probably are other ways that differ more from the one I mentioned.

First step is the same. The Virus goes across first. Next either antivirus or the computer goes next and the virus comes back. then either the computer ( if Antivirus is across) or Antivirus ( if computer is cross) and last the virus is brought cross

If you don't mind, I'm just gonna post a new one:
On the ground level of a hotel there are three maiden and three vampires. There is an elevator that can take a maximum of 2 people, but can't move without anyone inside. Every time there are more vampires than maiden in one place the vampires kill the maiden. If the number of maiden and vampires that are in the same place are equal, that's okay. How can all six safely get to the top level?
Important: Everyone has to leave the elevator when getting to the top or the ground level, you can't have someone leave the level again immediately after arriving while staying in the elevator the entire time.

I may not have been able to explain the important thing there clearly. So, for better understanding, here's an example of what doesn't work:
Let's say one vampire and no maiden are on the top level. Now you send the elevator up with one vampire and one maiden. The maiden stays on the top level, while the vampire goes back down without ever leaving the elevator. On the top level you'd have one each, which is fine.
The reason this doesn't work is everyone needs to leave the elevator after it's arrived on the top level. At that point there are two vampires but just one maiden on the top level. Even if one of the vampires is As a result the vampires'll kill the maiden.
Later

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bash7353

部下の手柄は上司のもの
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Posts: 419

Re: Kogorous Riddle Thread and eworms Deduction Thread

Postby bash7353 » January 3rd, 2014, 5:09 pm

So here's my second try:

[spoiler]First the user transports the virus across and comes back alone. Then it looks like this:

Code: Select all

User
Computer     Virus
Antivirus

Afterwards the user brings the computer to the other site and brings the virus back.

Code: Select all

User
Antivirus     Computer
Virus

The user transports the antivirus and returns alone.

Code: Select all

User         Computer
Virus        Antivirus

Then the user takes the virus across and... Done.[/spoiler]

I hope this time it's correct. The only thing I changed from the first solution is bringing the computer rather than the antivirus to the other side first. I'm not sure if they are possibilities besides these two, everything I did felt forced...
"Jo mere uenig du er med nogen, jo pænere skal du tale til dem. Tal om indholdet. Brug tid på indholdet. Forhold dig til det, der diskuteres. Lyt til, hvad der bliver sagt, i stedet for hvem der siger det. Hvis vi skal gøre det her med demokratiet bedre, så starter vi der."
描いた夢は叶わないことの方が多い
秀れた人を羨んでは自分が嫌になる
浅い眠りに押し潰されそう夜もある
優しい隣人が陰で牙を向いていたり

惰性で観てたテレビ消すみたいに生きる
ことを時々辞めたくなる

人生は苦痛ですか 成功が全てですか
僕はあなたにあなたに ただ逢いたいだけ
信じたい嘘 効かない薬 帰れないサヨナラ
叫べ叫べ叫べ   逢いたいだけ
Kogorou
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Re: Kogorous Riddle Thread and eworms Deduction Thread

Postby Kogorou » January 28th, 2014, 12:51 am

Ah this is still alive how awesome is that.
Damn classes I will post my solution later :)
Divy Kala
Posts: 1

Re: Kogorous Riddle Thread and eworms Deduction Thread

Postby Divy Kala » January 31st, 2014, 7:21 am

Hey everyone.I've been looking around this forum for about a month now when finally someone posted. Anyway, if this forum is still alive here is my solution to the puzzle above

If you don't mind, I'm just gonna post a new one:
On the ground level of a hotel there are three maiden and three vampires. There is an elevator that can take a maximum of 2 people, but can't move without anyone inside. Every time there are more vampires than maiden in one place the vampires kill the maiden. If the number of maiden and vampires that are in the same place are equal, that's okay. How can all six safely get to the top level?
Important: Everyone has to leave the elevator when getting to the top or the ground level, you can't have someone leave the level again immediately after arriving while staying in the elevator the entire time.


[spoiler]Firstly, two vampires go and one returns, leaving one vampire on the top level. Next, two vampires go again and one of them brings the elevator to the bottom floor leaving two vampires on the top floor and 1 on the bottom floor with the other three maidens. This time two of the maidens go to the top floor ,and down goes the elevator with one vampire and one maiden leaving two maidens and two vampires on the bottom floor and two alternates on the top floor. Then two maidens go while the vampire on the far side gets the elevator back leaving 3 maidens on the top floor and 3 vampires on the bottom floor. Ahead of this it's just downhill - two vampires go, one returns then both of the vampires on the bottom floor go to the top floor with the elevator ending at the top floor.[/spoiler]
Initial understanding was far from a happy accident.
bash7353

部下の手柄は上司のもの
上司の失敗は部下の責任

Posts: 419

Re: Kogorous Riddle Thread and eworms Deduction Thread

Postby bash7353 » February 7th, 2014, 10:51 am

First post and absolutely correct, Divy Kala! Well done!

If you want to, you can leave a new puzzle for the rest of us to ponder over.
"Jo mere uenig du er med nogen, jo pænere skal du tale til dem. Tal om indholdet. Brug tid på indholdet. Forhold dig til det, der diskuteres. Lyt til, hvad der bliver sagt, i stedet for hvem der siger det. Hvis vi skal gøre det her med demokratiet bedre, så starter vi der."
描いた夢は叶わないことの方が多い
秀れた人を羨んでは自分が嫌になる
浅い眠りに押し潰されそう夜もある
優しい隣人が陰で牙を向いていたり

惰性で観てたテレビ消すみたいに生きる
ことを時々辞めたくなる

人生は苦痛ですか 成功が全てですか
僕はあなたにあなたに ただ逢いたいだけ
信じたい嘘 効かない薬 帰れないサヨナラ
叫べ叫べ叫べ   逢いたいだけ
dumytru
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Re: Kogorous Riddle Thread and eworms Deduction Thread

Postby dumytru » February 13th, 2014, 3:14 pm

Since nobody's posting anything, here's a quick puzzle.

Use the numbers 1,3,4,6 and the operations "+", "-", "*", "/" to get the number 24.
Example: (2 * 3) + 9 - 1 = 14.


Restrictions:
You have to use all the numbers, and a number should be used only once.
You may, though, use the operations as you wish. But you can use only the one's written above (so you can't use powers (2^3) )
Also, you can't do something like this: 36-14 = ...
Use the numbers as they are.
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Togop
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Re: Kogorous Riddle Thread and eworms Deduction Thread

Postby Togop » February 15th, 2014, 9:38 pm

These are all decimal numbers, right?
dumytru
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Re: Kogorous Riddle Thread and eworms Deduction Thread

Postby dumytru » February 15th, 2014, 10:17 pm

Togop wrote:These are all decimal numbers, right?


Yeah, but you may use float. (for example 1/2 = 0.5)
shinichi'sapprentice wrote:dumytru hasn't acted very 'evil-like', but that's his specialty though...


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bash7353

部下の手柄は上司のもの
上司の失敗は部下の責任

Posts: 419

Re: Kogorous Riddle Thread and eworms Deduction Thread

Postby bash7353 » February 15th, 2014, 10:51 pm

That was the hint I needed.

[spoiler]6 / (1 - 3/4)
= 6 / (1 - 0.75)
= 6 / 0.25
=24[/spoiler]
"Jo mere uenig du er med nogen, jo pænere skal du tale til dem. Tal om indholdet. Brug tid på indholdet. Forhold dig til det, der diskuteres. Lyt til, hvad der bliver sagt, i stedet for hvem der siger det. Hvis vi skal gøre det her med demokratiet bedre, så starter vi der."
描いた夢は叶わないことの方が多い
秀れた人を羨んでは自分が嫌になる
浅い眠りに押し潰されそう夜もある
優しい隣人が陰で牙を向いていたり

惰性で観てたテレビ消すみたいに生きる
ことを時々辞めたくなる

人生は苦痛ですか 成功が全てですか
僕はあなたにあなたに ただ逢いたいだけ
信じたい嘘 効かない薬 帰れないサヨナラ
叫べ叫べ叫べ   逢いたいだけ
dumytru
User avatar
Posts: 874

Re: Kogorous Riddle Thread and eworms Deduction Thread

Postby dumytru » February 16th, 2014, 12:37 am

googleearth wrote:That was the hint I needed.

[spoiler]6 / (1 - 3/4)
= 6 / (1 - 0.75)
= 6 / 0.25
=24[/spoiler]


Yup! :D
shinichi'sapprentice wrote:dumytru hasn't acted very 'evil-like', but that's his specialty though...


dumytru's Karaoke Project!
sstimson
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Re: Kogorous Riddle Thread and eworms Deduction Thread

Postby sstimson » March 27th, 2014, 12:16 am

What no new puzzle. well, let us do something about that. Name The Last site of the World's Fair.
Later

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Togop
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Re: Kogorous Riddle Thread and eworms Deduction Thread

Postby Togop » March 27th, 2014, 2:35 am

The Last site of the World's Fair shall be called Mike.
sstimson
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Re: Kogorous Riddle Thread and eworms Deduction Thread

Postby sstimson » March 27th, 2014, 11:39 pm

Might need to clarify. Last site means either the last site (location) where the fair was or the next site where it will be.
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